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How to determine electrical box size per NEC

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Here is a quick exercise:

  • Wires for two circuits are entering a junction box through one conduit.
  • On the other end, the circuits split into two branches
  • Two neutrals entering (current count = 2)
  • Two hots entering (current count = 4)
  • Two grounds entering (current count = 5)
  • Wire gauge is 12, so total volume is 5 * 2.25 = 12.25 cu inches

Does this calculation have to include wires that are exiting? I will have two 12/2 Romex. If this figures into calculation, 2x the volume is needed (24.5 cu inches).

Edit 1: I should clarify that this will be a junction box without any devices on it. On one end, a 1/2 inch LFMC is entering with a plastic connector, and on the other end, two 12/2 Romex wires will exit individually through a snap on connector each.


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